Difference between two dates in PHP

<?php
$date1 = "2015-01-23 00:20";
$date2 = "2015-01-23 05:30";
$seconds = strtotime($date2) - strtotime($date1);
$days    = floor($seconds / 86400);
$hours   = floor(($seconds - ($days * 86400)) / 3600);
$minutes = floor(($seconds - ($days * 86400) - ($hours * 3600))/60);
$seconds = floor(($seconds - ($days * 86400) - ($hours * 3600) - ($minutes*60)));
echo "$days Days, $hours Hrs $minutes mins $seconds sec";
?>

Difference between two dates in Javascript with demo

Enter values in mm/dd/yy hh:mm:ss format
First date and time
Second date and time
Result
In (decimal) hours
In (decimal) minutes
In seconds

Code:
<script type='text/javascript'>

function p (i){

return Math.floor(i / 10) + "" + i % 10;

}

function trunc (i){

var j = Math.round(i * 100);

return Math.floor(j / 100) + (j % 100 > 0 ? "." + p(j % 100) : "");

}

function calculate (form){

var date1 = new Date(form.date1.value);

alert(form.date1.value+"\n\n"+date1)

var date2 = new Date(form.date2.value);

var sec = date2.getTime() - date1.getTime();

if (isNaN(sec)){

alert("Input data is incorrect!");

return;

}

if (sec < 0){

alert("The second date ocurred earlier than the first one!");

return;

}

var second = 1000, minute = 60 * second, hour = 60 * minute, day = 24 * hour;

form.result_h.value = trunc(sec / hour);

form.result_m.value = trunc(sec / minute);

form.result_s.value = trunc(sec / second);

var days = Math.floor(sec / day);

sec -= days * day;

var hours = Math.floor(sec / hour);

sec -= hours * hour;

var minutes = Math.floor(sec / minute);

sec -= minutes * minute;

var seconds = Math.floor(sec / second);

form.result.value = days + " day" + (days != 1 ? "s" : "") + ", " + hours + " hour" + (hours != 1 ? "s" : "") + ", " + minutes + " minute" + (minutes != 1 ? "s" : "") + ", " + seconds + " second" + (seconds != 1 ? "s" : "");

}

</script>

<form id="form">

<table cellpadding="3">

<tr>

<td colspan="2" align="center">Enter values in <font color="#800000">mm/dd/yy hh:mm:ss</font> format</td>

</tr>

<tr>

<td>First date and time</td>

<td><input type="text" name="date1" /></td>

</tr>

<tr>

<td>Second date and time</td>

<td><input type="text" name="date2" /></td>

</tr>

<tr>

<td colspan="2" align="center"><input type="button" name="submit" value="Calculate" onclick="calculate(this.form)" /></td>

</tr>

<tr>

<td>Result</td>

<td colspan="2"><input type="text" name="result" readonly="readonly" size="40" /></td>

</tr>

<tr>

<td>In (decimal) hours</td>

<td colspan="2"><input type="text" name="result_h" readonly="readonly" /></td>

</tr>

<tr>

<td>In (decimal) minutes</td>

<td colspan="2"><input type="text" name="result_m" readonly="readonly" /></td>

</tr>

<tr>

<td>In seconds</td>

<td colspan="2"><input type="text" name="result_s" readonly="readonly" /></td>

</tr>

</table>

Calculate Number of days Between two dates except saturday & sunday or week off in PHP script

<?php
$strt_date = date_create('2015-m-1');
$end_date = date_create(date('Y-m-d'));
date_sub($strt_date, date_interval_create_from_date_string('1 day'));
$interval = date_diff($strt_date, $end_date);
$num=$interval->format('%a');
$x=1;
for($i=0;$i<$num;$i++){
  date_add($strt_date, date_interval_create_from_date_string('1 day'));
  $next_day=date_format($strt_date, 'd-m-Y');
  echo "<br>";
  $new_date = new DateTime($next_day);
  $weeknum=$new_date->format('w');
  if(($weeknum!=0)&&($weeknum!=6)){
	 echo "$x. not a holiday :$weeknum  $next_day ";
	 $x++;
  }
}
?>

How to take dates between two dates in php?

   $task_to_do = array();
   echo "
";
   $s = strtotime("START_DATE");
   $d = strtotime("END_DATE");
   $dif = 86400;
   $i=$s;
   $x=0;
   while ($i <= $d) {
      $dat = date("Y-m-d 00:00:00",$i);
      $t_s = date("Y-m-d 00:00:00",strtotime($dat));
      $t_e = date("Y-m-d 23:59:59",strtotime($dat));
      $task_to_do[$x]["start_date"] = $t_s;
      $task_to_do[$x]["end_date"] = $t_e;
      $i = $i+$dif;
      $x++;
   }
   echo "
";
   print_r($task_to_do);

How to calculate no of working days in php?

function getWorkingDays($startDate, $endDate){
   $begin=strtotime($startDate);
   $end=strtotime($endDate);
   if($begin>$end){
     echo "tartdate is in the future! 
";
      return 0;
   }else{
      $no_days=0;
      $weekends=0;
      while($begin<=$end){
         $no_days++; // no of days in the given interval
         $what_day=date("N",$begin);
         if($what_day>6) { // 6 and 7 are weekend days
            $weekends++;
         };
         $begin+=86400; // +1 day
      };
      $working_days=$no_days-$weekends;
      return $working_days;
   }
}

Dynamically Date Range reset in jQuery UI date picker

Removes the datepicker functionality completely. This will return the element back to its pre-init state. 
Code :
$( "#start_date" ).datepicker( "destroy" );
$( "#end_date" ).datepicker( "destroy" );

jQuery Date picker ui select date range picker

Jquery UI Datepicker select date range between Two days

$( "#start_date" ).datepicker({
   minDate: new Datenew Date(1999, 10 - 1, 25),
   maxDate: new Datenew Date(1999, 10 - 1, 30),
   defaultDate: "+1w",
   changeMonth: true,
   numberOfMonths: 2,
   onClose: function( selectedDate ) {
      $( "#end_date" ).datepicker( "option", "minDate", selectedDate );
   }
});

$( "#end_date" ).datepicker({
   minDate: new Datenew Date(1999, 10 - 1, 25),
   maxDate: new Datenew Date(1999, 10 - 1, 30),
   defaultDate: "+1w",
   changeMonth: true,
   numberOfMonths: 2,
   onClose: function( selectedDate ) {
      $( "#start_date" ).datepicker( "option", "maxDate", selectedDate );
   }
});

PHP Date functionality

<?php echo $date= date('Y-m-d h:i:s'); echo "
"; echo $validity=30; echo "
"; echo date ("Y-m-d h:i:s", mktime (date('h'),date('i'),date('s'),date('m'),date("d")+$validity,date('Y'))); ?>